(rad(5) +rad(11.ord3))90
T(k+1)= comb.de 90 luate cate k * ( 5^(1/2) )^90-k * ( 11^(1/3) )k =cmb.de90 luate cate k *5^(90-k)/2*11^k/3;
0<=k<=90 => k|6 : A={6*0;6*1;6*2;...;6*16} =>
sunt 17 numere rationale si 90-17 = 73 nr.irationale
Sper ca te am ajuat!