Compusul C este un alcool
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CnH2n+2O + Na => CnH2n+1O + 1/2H2
14n+18g..............11,2L H2
9,2g.....................2,24 L H2
(14n+18)2,24 = 103,04 <=> 31,36n=62,72 => n= 2
F.M alcool => C2H5-OH - alcool etilic
Prin urmare hidrocarbura A este etanul (C2H6 - H3C-CH3)
CH3-CH3 + Cl2 => CH3-CH2-Cl + HCl
CH3-CH2-Cl + H2O => CH3-CH2-OH + HCl
