vrainat 1
avand in vedere ca se cere x/y inseamna ca y≠0,deci putem imparti cu y numaratorul si numitorul
(2*(x/y)+(y/y))/((x/y)+2y/y)=(2x/y+1)/((x/y)+2)=11/10
fie x/y=z
(2z+1)/(z+2)=11/10
20z+10=11z+22
9z=12
z=12/9=4/3
x/y=4/3
vrainta 2
aplicam direct proprietatea fundamentala a proportiilor
20x+10y=11x+22y
9x=12y |:4
3x=4y |:y
3x/y=4 |:3
x/y=4/3
