CxH(2x-2)O3 C(x-2)H(2x-3)-CO-COOH
12x/(3·16)= 3/4 x/4 = 3/4 x = 3 acid = CH3-CO-COOH
2CH3-CO-COOH + H2O ⇒ CH3-COOH + CH3-CH(OH)-COOH + CO2
nX = 8,8/88 = 0,1 moli
teoretic : n hidroxiacid = nX/2 = 0,05 moli = 1/20 moli
practic : n hidroxiacid = 3/90 = 1/30 moli
η = 1/30 x20/1 x100 = 66,66%