Rezolvam ecuatia f(x) = 0
[tex]\displaystyle\\
x^2 -3x+2=0\\\\
x_{12} = \frac{-b\pm \sqrt{b^2-4ac} }{2a}= \frac{3\pm \sqrt{9-8} }{2}= \frac{3\pm \sqrt{1} }{2}=\frac{3\pm 1 }{2}\\\\
x_1 =\frac{3+ 1 }{2}=\frac{4}{2}=\boxed{\bf 2}\\\\
x_2 =\frac{3-1 }{2}=\frac{2}{2}=\boxed{\bf 1}\\\\
\Longrightarrow~~\boxed{\bf f(1) = f(2) = 0}\\\\
\Longrightarrow~\bf~f(0)\times f(1)\times f(2)\times f(3)\times \cdots \times f(2015) =\\\\=f(0)\times 0 \times 0 \times f(3)\times \cdots \times f(2015) = \boxd{\bf 0}[/tex]
