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Rezolvati ecuatia: 100(2x+1)+50(3x+1)=400

Răspuns :

100*2x+100+50*3x+50≈400
200x+100+150x+50≈400
200x+150x≈400-100-50
350x≈250
x≈250 supra 350
x≈0.71

impartim relatia data prin 50≠0
2(2x+1)+3x+1=8
4x+2+3x+1=8
7x+3=8
7x=5
x=5/7


verificare
100(10/7+1)+50(15/7 +1)=400
100*17/7+50*22/7=400
1700/7+1100/7=400
2800/7=400
400=400
adevarat, bine rezolvat