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Răspuns :

[tex]\Big{^{\sqrt{111}+11)}}\sqrt{111}-11 = \dfrac{(\sqrt{111}+11)(\sqrt{111}-11)}{\sqrt{111}+11}= \dfrac{\sqrt{111}^2-11^2}{\sqrt{111}+11} = \\ \\ =\dfrac{111-121}{\sqrt{111}+11} = \dfrac{-10}{\sqrt{111}+11} = -\dfrac{10}{\sqrt{111}+11} = -\dfrac{10}{11+\sqrt{111}}[/tex]