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A={X|x €N,x+2●(x-5) <_ 5 si B {y|y €N;y|8


Răspuns :

x+2(x-5)≤5
x+2x-10≤5
3x≤5+10
3x≤15
x≤15:3
x≤5 => A= {5, 4, 3, 2, 1, 0}, x€N
y/8 => y€D8 => B= {1, 2, 4, 8}, y€N