[tex]3 H_{2}+ N_{2}= 2NH_{3} [/tex]
[tex]M_{H2}=2*1=2 [/tex]
[tex]M_{NH3}=14+3*1=17 [/tex]
Aflam cati moli de H2 avem in cele 60 de g.
[tex]n= \dfrac{m }{M }= \dfrac{60}{2} =30 \ moli [/tex]
3 moli H2......... 2 moli NH3
30 moli H2......... x
[tex]x= \dfrac{30*2}{3} =20 \ moli\ NH3[/tex]
Deci raspunsul este D.
