abc=100a+10b+c
Rasturnatul lui abc=cba
cba=100c+10b+a
100a+10b+c=100c+10b+a
99a=99c
a=c=> conditia a=c si b={0,1,2...9]
101=101
111=111
121=121
.................
191=191 in total 10 numere (le numeri pre coloana lui b
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202=202
212=212
..............
292=292 in total 10 numere
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303=303
.................
393=393-=>10numere
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404-494= 10 numere
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505-595 10 n9mere
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909=909
............
999=999 10 nimere
In total 9*10=90 numere
