32.
x=suma
2x/3+15=ziua 1
x-(2x/3+15)=x-2x/3-15=x/3-15= rest
(x/3-15)×40%=(x/3-15)×2/5=2x/15 - 6=ziua 2
2x/3+15+2x/15-6+27=x
2x/3+2x/15+36=x
10x+2x+540=15x
3x=540
x=180 lei suma initiala
2×180/15-6=18 lei a cheltuit in ziua 2
sau
ziua 2 = 40% din restul dupa ziua 1 ⇒ 27 reprezinta 60% din restul dupa ziua1 ⇒ 27:60%=27×100/60=45 lei restul dupa ziua 1
⇒45×40%=18 lei a cheltuit in ziua 2
suma initiala x
ziua 1 = 2x/3+15
x-2x/3-15=45 (restul dupa ziua1)
x/3=60
x=180 lei
33.
(a+b)/2=5 a+b=10
(c+d+e)/3=25 c+d+e=75
(f+g+h+i+j)/5=125 f+g+h+i+j=625
(a+b+c+d+e+f+g+h+i+j)=(10+75+625)/10=710/10=71
