x/y+x+1/y+1+x+2/y+2=3
[tex]\it \dfrac{x}{y} +x+\dfrac{1}{y} +1+x+\dfrac{2}{y}+2=3 \Rightarrow \dfrac{x}{y} +x+\dfrac{1}{y} +x+\dfrac{2}{y}=0 \Rightarrow
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\Rightarrow x+xy+1+xy+2=0 \Rightarrow x+2xy = -3 \Rightarrow x(1+2y) =3
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3= -3\cdot(-1) = -1\cdot(-3) = 1\cdot3= 3\cdot1[/tex]
