[tex]4) \quad {{3^2}^4}^0 + {{5^4}^1}^{100} : 25-10^4:2^3\cdot 5^3 = \\ ={3^{2}}^1+ {5^4}^1 : 25-(2\cdot 5)^4:2^3\cdot 5^3 = \\ = 3^2+5^4:5^2-2^4\cdot 5^4:2^3\cdot 5^3 = \\ =3^2+5^2-5^4\cdot 5^3\cdot 2^4:2^3= \\ = 3^2+5^2 - 5^{4+3}\cdot 2^{4-3} = \\ = 3^2+5^2-5^7\cdot 2 = \\ =9 +5^2\cdot(1-5^5)\cdot 2 =\\ = 9+25\cdot (1-3125)\cdot 2= \\ =9+25\cdot (-3124)\cdot 2 = \\ = 9 -156200 = \\ = -156191[/tex]
[tex]5) \quad 4(x-2)-5 = 123 \\ 4x-8-5 = 123 \\ 4x-13 = 123 \\ 4x = 123+13 \\ 4x = 136 \\ x = 136:4 \\ x =34 \in \mathbb_N \Rightarrow $ S = \big\{34\big\}[/tex]
Atat am putut face acum... Imi poti da abuz.
