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(2×3×1+72):7=
200-100:10+1×7×8×0-(45+45)=


Răspuns :

1) = ( 6 + 72) : 7 = 78 :7 =  11 intregi 1/7 
2)  = 200 - 10 + 0 - 90 = 190 - 90 = 100  
(2•3•1+72):7=
(6+72):7=
78:7=11,14

200-100:10+1•78•0-(45+45)=
200-10+0-90=
190-90=100