c) [tex] \frac{1}{2} + \frac{5}{6} * \frac{1}{25} - \frac{15-1}{90} [/tex]
[tex] \frac{1}{2} + \frac{5}{6*25} - \frac{14}{90} =\ \textgreater \ \frac{1}{2} + \frac{5}{150} - \frac{14}{90} [/tex]
(vom aplifica pe [tex] \frac{1}{2} [/tex] cu 225, pe [tex] \frac{5}{150} [/tex] cu 3 iar pe [tex] \frac{14}{90} [/tex] cu 4 pentru a le aduce la acelasi numitor(450)
[tex]=\ \textgreater \ \frac{225}{450} + \frac{15}{450} - \frac{56}{450} = \frac{184}{450} [/tex]
Vom simplifica cu 2: [tex]= \frac{92}{225} [/tex]
d)[tex] \frac{3}{9} : \frac{6}{10} +( \frac{1}{4} - \frac{5}{10} ) ^{2} [/tex]
[tex] \frac{3}{9} * \frac{10}{6} + (\frac{10}{40} + \frac{20}{40})^2 [/tex]
