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[tex][ \frac{2x+1}{3} ]+[ \frac{4x+5}{6} ]= \frac{5x+1}{3} \\ \\ E~corecta~rezolvarea: \\ {[ \frac{2x+1}{2} ]} +{[ \frac{4x+5}{6} ] -2\ \textless \ \frac{4x+2+4x+5}{6} \leq {[ \frac{2x+1}{2} ]} +{[ \frac{4x+5}{6} ]} \\ [/tex]