functiilede gradul intai,
dar in mod normal este O SINGURA functie
fie functia cautata de forma f(x)=ax+b
atunci
a(2x-1) +b=3x+2
2ax-a+b=3x+2,∀x∈R
atunci
2ax=3x
si
-a+b=2
adica
2a=3
si
-a+b=2
deci a=3/2
si b=2+a=2+3/2=7/2
deci f(x) =3x/2+7/2
verificare
f(2x-1) =(3/2) *(2x-1)+7/2=3x-3/2+7/2=3x+4/2=3x+2, adevarat , bine rezolvat