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18(1/6)^2-ln1/6 cine mă ajuta

Răspuns :

   
[tex]\displaystyle\\ 18 \times \Big(\frac{1}{6}\Big)^2 - \frac{\ln(1)}{6} =\\\\ = 18 \times \Big(\frac{1}{36}\Big) - \frac{0}{6} =\frac{18}{36} -0= \boxed{\bf \frac{1}{2} } [/tex]