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Aflati media aritmirica a nr 4.2,1.23,45.6

Răspuns :

M.a= (4,2+1,23+45,6)/3=51,03/3=17,01


[tex]ma= \frac{4,2+1,23+45,6}{3}
ma= \frac{51,03}{3}
ma=17,01[/tex]