CH3-CH2-OH + [O] ⇒ CH3-CH=O + H2O
K2Cr2O7 + 4H2SO4 ⇒ K2SO4 + Cr2(SO4)3 + 4H2O + 3[O]
n ald. = 100/60 ·26,4/44 = 10/6 · 0,6 = 1 mol
n ald./nK2C2O7 = 3/1
nK2Cr2O7 = n ald./3 = 1/3 moli Vs = (1/3)/(1/3) = 1 l
b) n alcool = 1/3 moli m = 1/3 ·46 = 15,33 g
Vs = (1/3)/(1/6) = 2 l