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aratati ca daca a supra 3= b supra 2 , atunci (14 a- 21b +1) la puterea 2013 = 1

Răspuns :

a/3 = b/2  =>  2a=3b

[tex] (14a-21b+1)^{2013} = (7*2a -7*3b +1)^{2013} = [7(3b-3b) + 1]^{2013} =1 1^{2013} = 1 [/tex]
Fie a/3=b/2=k
a=3k
b=2k
(14a-21b+1)^2013=1
(14•3k-21•2k+1)^2013=1
(42k-42k+1)^2013=1
1^2013=1
(A)