[tex]\displaystyle Se~da:\\ \\
m=2,4t=2400kg\\ \\
t=14min=840s\\ \\
P=35,2kW=35200W\\ \\
\Delta h=?m\\ \\
Formule:\\ \\
Putem~sa~reformulam~si~sa~spunem~ca~spatiul~parcurs\\
de~telecabina~si~este~diferenta~de~nivel.\\ \\
P=F\times v\\ \\ \\[/tex]
[tex]\displaystyle Presupunem~ca~telecabina~urca~drept~vertical,~deci:\\ \\
G=F=m\times g\\ \\ \\
\Delta h=v\times t\Rightarrow v=\frac {\Delta h}t\\ \\ \\
P=m\times g\times \frac{\Delta h}{t}\\ \\
\Delta h=\frac{P\times t}{m\times g}\\ \\ \\
Calcule:\\ \\
\Delta h=\frac{35200\times 840}{2400\times 10}=1232m[/tex]
