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calculati: (2+4+6+8...+100)-(1+3+5+7+...+99) in doua moduri

Răspuns :

Răspuns:

Explicație pas cu pas:

( 2+4+6+8+......+100) - ( 1+3+5+7+....+99) =

= 2 × (1+2+3+4+.....+50) - { [ ( 99-1):2+1] × (1 +99):2} =

                                             → aplic formula sumei lui Gauss

= 2 × 50 × 51 : 2 - ( 50 × 100 : 2 ) =

= 50 × 51 - 50 × 50 =

= 50 × (51-50) =

= 50 × 1 =

= 50 → primul mod

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Al doilea mod:

2+4+6+8+......+100 -  =>  50 termeni

 1+3+5+7+......,+99     => ( 99-1):2+1 = 49+1=50 termeni

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= ( 2 - 1 ) + ( 4-3) + ( 6-5) + ( 8-7) + ....... + ( 100 -99) =

= 1 + 1 + 1 + 1 + 1 + ........... + 1  → de 50 de ori : (1+2+3+.....+50)

= 50 × 1 =

= 50