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Aflați numerele naturale a si b stiind ca axb =120 si ax(b+5)=160

Răspuns :

a × b=120
a × (b+5)=160
a × b+a×5=160
120+a×5=160
a×5=40
a=8

a×b=120
8×b=120
b=120:8=15

a=8
b=15
a×(b+5) = 160
a×b + a×5 = 160
a×b = 120
120 + a×5 = 160
a×5 = 160-120
a×5 = 40
a = 40:5
a = 8

b = 120 : 8 = 15