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In progresia aritmetica (an) n>1 , a3=11, a11=3 . Calculati a7

Răspuns :

a3=a1+2r=11
a11=a1+10r=3
a1=11-2r
11-2r+10r=3
8r=3-11
r=-8/8=-1

a1=11-2·(-1)=13

a7=a1+6r=13-6=7
a3=a1+2r=11
a11=a1+10r=3     /*(-1)  
a1+2r=11
-a1-10r=-3             +
________________
-8r=8
8=-1
=>a1=13
a7=13+6*(-1)=13-6=7