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calculalti (2-√2)^2+2√2(2-√2)+2

Răspuns :

(2-√2)^2+2√2(2-√2)+2   radicalul il voi scrie r
4-2*2*r2+2   +  4r2-4+2=
4-4r2+2  + 4r2-4+2 = 
4+2-4+2 = 
6-4+2=
2+2=4




[tex]\it (2-\sqrt2)^2+2\sqrt2(2-\sqrt2)+2 = (2-\sqrt2(2-\sqrt2+2\sqrt2) +2= \\\;\\ = (2-\sqrt2)\cdot(2+\sqrt2)+2=2^2-(\sqrt2)^2 +2 = 4-2+2=4[/tex]