[tex]\displaystyle \sqrt{4x-3}=2x-3,x\ \geq \ \frac 34\\ \\
4x-3=(2x-3)^2\\ \\
4x-3=4x^3-12x+9\\ \\
4x^2-16x+12=0\\ \\
x^2-4x+3=0\\ \\
\left \{ {{x_1+x_2=4} \atop {x_1\times x_2=3}} \right. \Leftrightarrow \left \{ {{x_1=1} \atop {x_2=3}} \right. \\ \\
Daca~controlam~x=1,~obtinem:\\ \\
\sqrt{4*1-3}=2*1-3\\ \\
1=-1,~ceea~ce~nu~e~adevarat!\\ \\
S=\{3\}
[/tex]
