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Se considera functiile f,g:R→R, f(x)=[tex] 2x^{2} -3x+1[/tex] , g(x)=[tex] x-2[/tex] . Calculati
(f °g)(1) .


Răspuns :

(FoG)(1) = F(G(1)) = F(-1) = 2+3+1 = 6

(f°g)(1)=f(g(1))=f(1-2)=f(-1)=2*(-1)²+3*(-1)+1=2+3+1=6
as simple as that!