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Daca x apartine (0, pi/2) si cos x=5/13, aratati ca tg x=12/5. Va rog!

Răspuns :

sin x=+√(1-cos²x)=√(1-25/169)=12/13 am luat cu plus pt ca in primul cadran sinx>0
tgx=sinx/cos x= (12/13):(5/13) =12/5 as simple as that!