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Determinati perechile de numere naturale (x,y)care satisfac egalitatea:(x*y+79*5):(304-29)*5-177=73

Răspuns :

(x×y+79*5):(304-29)×5-177=73
(x×y+395) : 275×5 = 73+177
(x×y+395):275×5 = 250
(x×y+395) : 275 = 250:5
(x×y+395):275 = 50
x×y+395 = 50×275
x×y+395 = 13750
x×y = 13750-395
x×y = 13355
13355 = 5×2671 ; 2671 nr prim
13355=1×13355

(x,y) = (1 , 13355) ; (5 , 2671) ; (13355 , 1) ; (2671 ,5)