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(ABCD)patrat
AB=10 CM
AC=? DIAGONALA
Apatrat=?
Ppatrat=?


Răspuns :

AC=ABrad2=10rad 2 cm
A=AB^2=100cm^2
P=4AB=40cm
diagonala patratului = L[tex] \sqrt{2} [/tex]
AC = 10[tex] \sqrt{2} [/tex] cm 

A = L^2 = 10^2 = 100 cm^2 
P = L x 4 = 10 x 4 = 40 cm