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[1,1 (6)-0, (3)]:3intregi 1 supra 3
2) 2 (x-3)=6


Răspuns :

1) 1,1(6)=116-11/90=105/90=21/18=7/6
0,(3)=3/9=1/3
3 intregi 1/3 =3×3+1/3=10/3
[7/6-1/3]:10/3 amplificam pe 1/3 cu 2
[7/6-2/6]:10/3 = 5/6×3/10=3/12=1/4

2) 2x-6=6
2x=12
x=12:2
x=6