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rezolvati ecuatia (x-2)la a doua-(x-3)(x+3)=9
Dau funda


Răspuns :

(x-2)^2 - (x-3)(x+3) = 9
x^2 - 4x + 4 - x^2 + 9 = 9
-4x + 4 = 0
-4x = -4
x= 1
[tex](x-2)^2-(x-3)(x+3)=9 x^2-4x+4-(x^2-9)=9 x^2-4x+4-x^2+9=9 -4x+4=0 -4x=-4 x=1 [/tex]