a,b,c= numerele;
a+b+c=120;
b=3a=>a=b:3
b=c-50=>c=50+b;
Acum inlocuim:
b:3+b+b+50=120;
{il amplificam pe primul b cu 3 si pe al doilea b cu 3}
b/3 +3b/3+ 3b/3=120-50;
7b/3=70;
7b:3=70;
7b=70×3;
7b=210;
b=210:7;
b=30=>a=30:3=10;
=>c=30+50=80;
Raspuns: Numerele sunt: 10;30;80
Verificare:10+30+80=40+80=120
