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f(x) = 4x - 3
g(x)=3-2x
cum se calculeaza ( g o f ) ( 1 ) ?


Răspuns :

[tex]f(x) = 4x-3 \\ g(x) = 3-2x \\ \\ (g$ \circ$ $f)(x) = g\Big(f(x)\Big) = g(4x-3) = 3-2\cdot (4x-3) = 3-8x+6 = \\ \\ = 9-8x \\ \\ \Rightarrow (g$ \circ$ $f)(x) = 9-8x\\ \\ (g$ \circ$ $f)(1) =9-8\cdot 1 = 9-8 = 1[/tex]