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2005:{572-[9×(4×X+1)+108 ]:3}=5

Răspuns :

2005:{572-[9×(4×X+1)+108 ]:3}=5
572-[9(4x+1)+108]:3=2005:5
[9(4x+1)+108]:3=572-401
36x+9+108=171x3
36x=513-117
x=396:36
x=11