[tex]n = \text{numarul de divizori.}\\\\
4800= 2^6 \times 3 \times 5^2 \\
\Longrightarrow n= (6+1)(1+1)(2+1)= 7\times2\times3 = \boxed{42 \text{ divizori}}\\\\
540=2^2\times3^3\times5 \\
\Longrightarrow n= (2+1)(3+1)(1+1)= 3\times4\times2 = \boxed{24 \text{ divizori}}\\\\
3060=2^2 \times 3^2 \times 5 \times 17\\
\Longrightarrow n= (2+1)(2+1)(1+1)(1+1)= 3\times3\times2\times2 = \boxed{36 \text{ divizori}}\\\\
[/tex]
