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(√7-√5)²=
va rog ajutorr


Răspuns :

[tex] (a-b)^{2}= a^{2}-2ab+ b^{2} \\ ( \sqrt{7}- \sqrt{5} )^2= (\sqrt{7}) ^2-2 \sqrt{7} \sqrt{5}+ (\sqrt{5})^{2}= \\ =7-2 \sqrt{35}+5= \\ =12-2 \sqrt{35} .[/tex]