22,4 L= 22400 mL
Un mol de substanta are un volum de 22,4 L in conditii normale. Asta inseamna conform transformarii 22400 mL.
Calculam masele moleculare pentru substantele indicate:
[tex]M_{P}=31 [/tex]
[tex]M_{Mg}=24 [/tex]
[tex]M_{H2}=2*1=2 [/tex]
[tex]M_{HCl}=1+35,5=36,5 [/tex]
Avem:
M g substanta X (1 mol)........22400 mL
m g substanta X...... 0,5 mL
[tex]m= \dfrac{0,5*M}{22400} \ g[/tex]
Aplicam aceasta formula peste tot si obtinem:
[tex]m_{P} = \dfrac{0,5*31}{22400}=0,0007 \ g [/tex]
[tex]m_{Mg}= \dfrac{0,5*24}{22400}=0,0005 \ g [/tex]
[tex]m_{H2}= \dfrac{0,5*2}{22400}=0,000045 \ g [/tex]
[tex]m_{HCl}= \dfrac{0,5*36,5}{22400}=0,0008 \ g [/tex]
