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Aflati numerele x, y, z, stiind ca sunt invers proportionale cu numerele 2,3si 6 si ca 3x plus 2y-5z=64

Răspuns :

2x=3y=6z   y=2x/3    z=2x/6=x/3
3x+2y-5z=64
3x+2×2x/3-5×x/3=64
3x+4x/3-5x/3=64
9x+4x-5x=192
8x=192
x=24
y=2×24/3=16
z=24/3=8