citind toata problema , se deduce ca se obtine benzen din acetilena !
a.
-calculez masa molara a substantei A , din densitatea relativa
d=M,A/M aer--->.2,698= M/29----> M=78g/mol
-deduc formula moleculara a lui A
100g......7,6gH........(100-7,6)gC
78.............x....................y
x=6gH--------> n= m/M=6g/1g/mol= 6H
Y=72gC-----> n= 72g/12g/mol=6C
A este C6H6
b.
3mol...........1mol
3C2H2---> C6H6 trimerizarea acetilenei
3x22,4l.........78g
x..................800000x0,88g (m= roxV= 0,88g/mlx800000ml)
x=V,teoretic= 606500 l acetilena
V,practic va fi mai mare, pentru a se compensa pierderile
V,pr= 606,5x100/90=674000 l
c.
1mol..................................1mol
C6H6 + C2H5Cl---> C6H5-C2H5 + HCl
78g......................................104g
800000x0,88............................x.....................................calculeaza !!!!
si verifica,te rog, calculele !!!
