[tex]\displaystyle \text{Se da:}\\ \\
V_1=5l=0,005m^3\\ \\
V_2=0,5l=0,0005m^3\\ \\
\rho_1=1030\frac{kg}{m^3}\\ \\
\rho_2=800\fr+ac{kg}{m^3}\\ \\
\rho=?\frac{kg}{m^3}\\ \\ \\
Formule:\\ \\
\rho=\frac{m}{V}\\ \\
\rho=\frac{m_1+m_2}{V_1+V_2}\\ \\
\rho=\frac{\rho_1\times V_1+\rho_2\times V_2}{V_1+V_2}\\ \\ \\
Calcule:\\ \\
\rho=\frac{1030\times 0,005+800\times 0,0005}{0,005+0,0005}\approx 1009\frac{kg}{m^3}[/tex]
