√1=1
[1]=1
√2=≈1,4
[1,4]=1
[√3]=[1,7]=1
suma primilor 3 termeni= 3
√4=2
[2]=2
......
[√8]=2 suma urmatorilor 5 termeni este 2
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√9=3
[3]=3
........................
[√15]=3 7 termeni cu partea intreaga 3
--------------------------------------------
√16=4
[4]=4
....................
[√20]=4 5 termeni cu partea intreaga 4
Se insumeaza
3*1+5*2+7*3+5*4=3+10+21+20=54
