specific ca nu stiu sigur daca e bine..daca nu e bine sterge...sau raporteaza ca nu ma supar
bd+dc=bc
perimetru abc=ab+bc+ac
50=ab+bc+ac
50=ab+bd+dc+ac
petrimetrul lui adb=ad+db+ab
30=ad+db+ab
perimetrul lui adc=ad+dc+ac
32=ad+dc+ac
adunam doua sisteme
30=ad+db+ab
32=ad+dc+ac
62=2ad+bd+ab+dc+ac
obdervam
50=ab+bd+dc+ac
62=2ad+bd+ab+dc+ac adun sistemele
112=2ab+2bd+2dc+2ac+2ad
112=2(ab+bd+cd+ac+ad)
56=ab+bd+cd+ac+ad
dar bd+dc=bc
56=ab+bc+ac+ad
dar ab+bc+ac=petrimetru abc=50
56=50+ad
ad=56-50
ad=6
mai am facut pe o foaie..si tot 6 mi-a dat