Avem:
a : b = c r
a = b × c + r
c = b : 4 ==> b = 4×c = 4×2×r = 8×r
r = c : 2 ==> c = 2 × r
b + c + r = 99
Aflam:
inlocuim in ultima relatie in functie de r
8 × r + 2 × r + r = 99
11 × r = 99
r = 99 : 11
r = 9 (restul)
c = 2 × 9 = 18 (catul)
b = 8 × 9 = 72 (impartitorul)
a = 72 × 18 + 9 = 1296 + 9 = 1 305 (deimpartitul)
Reconstituirea impartirii:
1 305 : 72 = 18 rest 9