Se da:
V1=6m³
p1=120atm=120*10⁵Pa
t1=27°C=300K
a)T2=273K, P2=10⁵Pa, V2=?m³
b)M=32kg/kMol=0,032kg/mol, m=?kg
Formule:
a)Formula generala pentru orice transformare a unui gaz:
p1*V1/T1=p2*V2/T2, de unde:
V2=p1*V1*T2/T1*p2
b)Din ecuatia Clapeyron-Mendeleev:
p1*V1=m*R*T1/M
m=p1*V1*M/R*T1
Calcule:
a)V2=120*10⁵*6*273/300*10⁵=655,2m³
b)m=120*10⁵*6*0,032/8,31*300≈924kg