[tex]\displaystyle \text{24. Se da:}\\ \\
V=25L=0,025m^3\\ \\
m=1kg\\ \\
p=3MPa=3000000Pa\\ \\
M=0,032\frac{kg}{mol}\\ \\
T=?K\\ \\ \\
\text{Formule:}\\ \\
\text{Din formula extinsa a lui Clapeyron-Mendeleev:}\\ \\ \\
p\times V=\frac{m}{M}\times R\times T\\ \\
T=\frac{p\times V\times M}{m\times R}\\ \\ \\
\text{Calcule:}\\ \\
T=\frac{3000000\times 0,025\times 0,032}{1\times 8,31}\approx 288,8K[/tex]
[tex]\displaystyle \text{25. Se da:}\\ \\
t=7^\circ=280K\\ \\
p=83kPa=83000Pa\\ \\
M=0,028\frac{kg}{mol}\\ \\
\rho=?\frac {kg}{m^3}\\ \\ \\
\text{Formule:}\\ \\
\text{Din ecuatia extinsa lui Clapeyron-Mendeleev:}\\ \\
p\times V=\frac{m}{M}\times R\times T\\ \\
p\times V=\frac{\rho\times V}{M}\times R\times T\\ \\
p=\frac{\rho}{M}\times R\times T\\ \\
\rho=\frac{p\times M}{R\times T}\\ \\ \\
\text{Calcule:}\\ \\
\rho=\frac{83000\times 0,028}{8,31\times 280}\approx 1\frac{kg}{m^3}[/tex]
