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A+b=5
B+c=6. 2a+5b+3a=?

Daca a+b=10
A+c=11
12a+116+c=?


Răspuns :

2a+5b+3a=?
Aplicam distributivitatea numerelor: (2+5+3)·(a+b+a)=?
10·(10+a)=?
a= 10:10
a=1
Daca a+c=11 at c= 11-1 c=10
12a+ 116+c=?
12·1+ 116+10=
=12+126=
=138

SUCCES!!!