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x*2+4+4x=16
help!
Am citit ca se rezolva prin delta sau ceva gen...


Răspuns :

x²+4+4x=16
x²+4x+4-16=0
(x+2)²-4²=0
(x+2+4)(x+2-4)=0
(x+6)(x-2)=0
x₁=-6
x₂=2


sau cu Δ
x²+4+4x=16
x²+4x+4-16=0
x²+4x-12=0
Δ=b²-4ac=4²-4x1x(-12)=16+48=64=8²
x₁,₂=-b+-√Δ/2a
x₁=-4+√64/2=-4+8/2=4/2=2
x₂=-4-√64/2=-4-8/2=-12/2=-6