Rezolvare:
a). ab+ac=520
b+c=52
In prima relatie dam factor comun pe a si avem:
a(b+c)=520
a×52=520
a=10
b).ab-ac=45
b-c=9
Dam factor comun pe a si avem:
a(b-c)=45
a×9=45
a=5
c).ab+ac+70=170
ab+ac=170-70=100
a=25
25 (b+c)=100
b+c=4
d).ab-ac-48=2
ab-ac=2+48=50
a=10
10 (b-c)=50
b-c=50/10=5
Sper ca te.am ajutat!!